Spectral Efficiency

Problem

Return the spectral efficiency in bits per second per hertz:

SE = capacity_bps / bandwidth_hz

Hint

Spectral efficiency is the capacity normalized by bandwidth.

case 1

in: [1000000,100000]

expected: 10

case 2

in: [3000000,1000000]

expected: 3

case 3

in: [0,20000]

expected: 0

case 4

in: [56000,56000]

expected: 1

Starter codePython

def spectral_efficiency(capacity_bps, bandwidth_hz):
    # Your code here
    pass

4 test cases · run your code against them in the editor