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HardTime Seriests-266

Walk-Forward Efficiency

Problem

Compute walk-forward efficiency as 1 - mean(oos_errors) / mean(is_errors).

Return 0.0 when either list is empty or the in-sample mean is zero. Negative values mean out-of-sample performance degraded relative to in-sample.

Hint

A value near 0 means performance held up out of sample.

Test cases

case 1
in: [[1,1,1],[1.2,1.2,1.2]]
expected: -0.19999999999999996
case 2
in: [[2,2],[2,2]]
expected: 0
case 3
in: [[1,2],[3]]
expected: -1
case 4
in: [[],[]]
expected: 0
Starter codePython
def walk_forward_efficiency(is_errors, oos_errors):
    # Your code here
    pass

4 test cases · run your code against them in the editor