Standard Error of Kurtosis

Problem

The standard error of the sample excess kurtosis is 2 * SE_skew * sqrt((n^2 - 1) / ((n - 3)(n + 5))) with SE_skew = sqrt(6n(n-1)/((n-2)(n+1)(n+3))).

Given the sample size n > 3, return the standard error.

Hint

Build it from the skewness standard error first.

case 1

in: [10]

expected: 1.334248769989982

case 2

in: [100]

expected: 0.47833113299481334

case 3

in: [4]

expected: 2.618614682831909

Starter codePython

def standard_error_of_kurtosis(n):
    # Your code here
    pass

3 test cases · run your code against them in the editor