Bits per Byte from NLL

Problem

Convert a total negative log-likelihood in nats to bits per byte: total_nll / (ln(2) * num_bytes). Return 0.0 when num_bytes <= 0.

case 1

in: [5.545177444479562,8]

expected: 1

case 2

in: [10,0]

expected: 0

case 3

in: [0,4]

expected: 0

case 4

in: [22.18070977791825,4]

expected: 8

Starter codePython

import math
def bits_per_byte(total_nll_nats, num_bytes):
    # Your code here
    pass

4 test cases · run your code against them in the editor