MDC95

Problem

Return the 95 percent minimal detectable change 1.96 * sqrt(2) * sd * sqrt(1 - reliability). Return 0.0 when sd <= 0 or reliability is outside [0, 1].

Hint

It equals 1.96 * sqrt(2) times the standard error of measurement.

Test cases

case 1

in: [10,0.75]

expected: 13.85929291125633

case 2

in: [15,0.91]

expected: 12.473363620130694

case 3

in: [10,1]

expected: 0

case 4

in: [10,0]

expected: 27.71858582251266

case 5

in: [0,0.5]

expected: 0

Starter codePython

def mdc95(sd, reliability):
    # Your code here
    pass

5 test cases · run your code against them in the editor