Information Fraction

Problem

Return the information fraction current_n / planned_n for an interim analysis. Return 0.0 when planned_n <= 0.

Hint

It is the proportion of planned information accrued.

case 1

in: [50,100]

expected: 0.5

case 2

in: [0,100]

expected: 0

case 3

in: [100,100]

expected: 1

case 4

in: [10,0]

expected: 0

case 5

in: [120,100]

expected: 1.2

Starter codePython

def information_fraction(current_n, planned_n):
    # Your code here
    pass

5 test cases · run your code against them in the editor