AIC Difference

Problem

Return AIC2 - AIC1, where AIC = -2*log_likelihood + 2*k for each model. Negative values favor the second model.

Hint

Compute each AIC, then subtract.

case 1

in: [-100,2,-110,5]

expected: 26

case 2

in: [-50,1,-50,1]

expected: 0

case 3

in: [-10,3,-12,2]

expected: 2

case 4

in: [-200,10,-180,10]

expected: -40

case 5

in: [-5,0,-6,0]

expected: 2

Starter codePython

def aic_difference(ll1, k1, ll2, k2):
    # Your code here
    pass

5 test cases · run your code against them in the editor