Required Sample Size for Mean

Problem

Return the smallest integer n with z*sigma/sqrt(n) <= margin, which is ceil((z*sigma/margin)^2). Return 0 if margin <= 0 or sigma <= 0.

Hint

Solve the margin-of-error inequality for n and round up.

case 1

in: [1.96,2,0.5]

expected: 62

case 2

in: [1.645,10,1]

expected: 271

case 3

in: [2,1,1]

expected: 4

case 4

in: [1.96,0,0.5]

expected: 0

case 5

in: [1.96,2,0]

expected: 0

Starter codePython

import math
def required_sample_size_mean(z_crit, sigma, margin):
    # Your code here
    pass

5 test cases · run your code against them in the editor