MediumStatisticsst-005

Normal Distribution PDF

Problem

Compute the probability density function of a normal distribution with mean mu and standard deviation sigma at point x:

pdf(x) = (1 / (sigma * sqrt(2π))) * exp(-(x - mu)^2 / (2 * sigma^2))

If sigma <= 0, return 0.0.

Hint

Don't forget to square sigma in the denominator of the exponent.

case 1

in: [0,0,1]

expected: 0.3989422804014327

case 2

in: [1,0,1]

expected: 0.24197072451914337

case 3

in: [0,0,2]

expected: 0.19947114020071635

case 4

in: [5,5,1]

expected: 0.3989422804014327

case 5

in: [0,0,0]

expected: 0

Starter codePython

import math
def normal_pdf(x, mu, sigma):
    # Your code here
    pass

5 test cases · run your code against them in the editor