Steady-State Availability

Problem

Steady-state availability of a repairable system with mean time between failures mtbf and mean time to repair mttr:

A = mtbf / (mtbf + mttr).

Return 0.0 when both are 0 or inputs are negative.

Hint

The system is up during the MTBF portion of each cycle.

case 1

in: [100,10]

expected: 0.9090909090909091

case 2

in: [50,50]

expected: 0.5

case 3

in: [10,0]

expected: 1

case 4

in: [0,0]

expected: 0

Starter codePython

def steady_state_availability(mtbf, mttr):
    # Your code here
    pass

4 test cases · run your code against them in the editor