Geometric CDF

Problem

Geometric cumulative distribution function for the number of trials until the first success.

P(X <= k) = 1 - (1 - p)^k for k >= 0. Return 0.0 for k < 0.

Hint

Use the complement: all k trials fail with probability (1 - p)^k.

case 1

in: [0.5,1]

expected: 0.5

case 2

in: [0.5,3]

expected: 0.875

case 3

in: [0.2,0]

expected: 0

case 4

in: [1,5]

expected: 1

case 5

in: [0.5,-1]

expected: 0

Starter codePython

def geometric_cdf(p, k):
    # Your code here
    pass

5 test cases · run your code against them in the editor