Normal PDF Value

Problem

Normal probability density function evaluated at x with mean mu and standard deviation sigma.

f(x) = exp(-(x - mu)^2 / (2 * sigma^2)) / (sigma * sqrt(2 * pi)). Return 0.0 when sigma <= 0.

Hint

The density peaks at the mean with value 1 / (sigma * sqrt(2 * pi)).

case 1

in: [0,0,1]

expected: 0.3989422804014327

case 2

in: [1,0,1]

expected: 0.24197072451914337

case 3

in: [0,0,2]

expected: 0.19947114020071635

case 4

in: [0,0,0]

expected: 0

Starter codePython

import math


def normal_pdf_value(x, mu, sigma):
    # Your code here
    pass

4 test cases · run your code against them in the editor