Poisson PMF

Problem

Poisson probability mass function with rate lam.

P(X = k) = lam^k * e^(-lam) / k!. Return 0.0 if lam < 0 or k < 0.

case 1

in: [2,0]

expected: 0.1353352832366127

case 2

in: [2,3]

expected: 0.1804470443154836

case 3

in: [1,5]

expected: 0.0030656620097620196

case 4

in: [3,-1]

expected: 0

Starter codePython

import math


def poisson_pmf(lam, k):
    # Your code here
    pass

4 test cases · run your code against them in the editor