One Cycle Peak Fraction

Problem

A one-cycle schedule rises linearly from 0 to peak_step and falls linearly from peak_step to total, never below zero.

Given t, peak_step, and total (with 0 < peak_step <= total), return the cycle fraction max(0, ...) where it is t / peak_step on the way up and (total - t) / (total - peak_step) on the way down.

Hint

Two linear branches sharing the peak at t = peak_step.

Test cases

case 1

in: [10,20,100]

expected: 0.5

case 2

in: [30,20,100]

expected: 0.875

case 3

in: [150,20,100]

expected: 0

Starter codePython

def one_cycle_peak_fraction(t, peak_step, total):
    # Your code here
    pass

3 test cases · run your code against them in the editor