MediumNLPnlp-202

CTC Blank Probability

Problem

Return the probability of an all-blank CTC path: the product of the per-frame blank probabilities.

An empty list gives 1.0, the empty product.

Hint

Per-frame probabilities multiply because frames are conditionally independent.

case 1

in: [[0.9,0.8]]

expected: 0.7200000000000001

case 2

in: [[]]

expected: 1

case 3

in: [[1,1]]

expected: 1

case 4

in: [[0.5,0.5,0.5]]

expected: 0.125

Starter codePython

def ctc_blank_probability(blank_probs):
    # Your code here
    pass

4 test cases · run your code against them in the editor