Circulant Matrix

Problem

Build the circulant matrix whose first row is the vector v.

Each subsequent row is the previous row shifted right by one, wrapping around: C[i][j] = v[(j - i) % n].

Hint

The matrix is uniquely determined by its first row because each diagonal is constant.

case 1

in: [[1,2,3]]

expected: [[1,2,3],[3,1,2],[2,3,1]]

case 2

in: [[1,0]]

expected: [[1,0],[0,1]]

case 3

in: [[5]]

expected: [[5]]

case 4

in: [[1,2,3,4]]

expected: [[1,2,3,4],[4,1,2,3],[3,4,1,2],[2,3,4,1]]

Starter codePython

def circulant_matrix(v):
    # Your code here
    pass

4 test cases · run your code against them in the editor