Differential Entropy of Exponential

Problem

Return the differential entropy in bits of an exponential distribution with rate parameter lambda:

h = (1 - ln(lambda)) / ln(2)

Assume lambda > 0.

Hint

The exponential distribution with rate 1 has entropy log2(e) bits.

case 1

in: [1]

expected: 1.4426950408889634

case 2

in: [0.5]

expected: 2.442695040888964

case 3

in: [2]

expected: 0.44269504088896344

case 4

in: [0.25]

expected: 3.442695040888964

Starter codePython

import math
def de_exponential(rate):
    # Your code here
    pass

4 test cases · run your code against them in the editor