Inverted Residual Expansion

Problem

Compute the expanded channel count of an inverted residual block, rounded up to a multiple of multiple.

Return ((cin * ratio + multiple - 1) // multiple) * multiple.

case 1

in: [24,6,8]

expected: 144

case 2

in: [32,3,8]

expected: 96

case 3

in: [16,3,8]

expected: 48

case 4

in: [30,1,8]

expected: 32

Starter codePython

def expanded_channels(cin, ratio, multiple):
    # Your code here
    pass

4 test cases · run your code against them in the editor