Implicit Circle Slope

Problem

For the circle x^2 + y^2 = r^2, implicit differentiation gives dy/dx = -x / y.

Given the coordinates of a point on the circle, return the tangent slope. Return None when y is zero (the tangent is vertical).

Hint

Differentiate both sides with respect to x and solve for dy/dx.

case 1

in: [1,1]

expected: -1

case 2

in: [2,0]

expected: null

case 3

in: [3,4]

expected: -0.75

Starter codePython

def implicit_circle_slope(x, y):
    # Your code here
    pass

3 test cases · run your code against them in the editor