Leaky ReLU Derivative Vector

Problem

The leaky ReLU is f(z) = z for z > 0 and f(z) = alpha * z otherwise, with derivative 1 for positive inputs and alpha elsewhere.

Given a list of pre-activations and alpha (default 0.01), return the derivative for each entry.

Hint

The derivative is piecewise constant; zero takes the negative branch.

case 1

in: [[1,-2,3,0]]

expected: [1,0.01,1,0.01]

case 2

in: [[-1,-1]]

expected: [0.01,0.01]

case 3

in: [[0.5,0,-0.5],0.1]

expected: [1,0.1,0.1]

Starter codePython

def leaky_relu_derivative(values, alpha=0.01):
    # Your code here
    pass

3 test cases · run your code against them in the editor