EasyCalculusca-144

Spherical Radial Laplacian

Problem

For a radially symmetric function f(r) = r^n, the Laplacian in spherical coordinates reduces to f'' + (2/r) * f'.

This equals n * (n + 1) * r^(n - 2). Given n and r > 0, return that value.

Hint

Only the radial part of the spherical Laplacian is nonzero for a radial function.

case 1

in: [2,3]

expected: 6

case 2

in: [1,2]

expected: 1

case 3

in: [0,5]

expected: 0

case 4

in: [-1,2]

expected: 0

case 5

in: [3,1]

expected: 12

Starter codePython

def spherical_radial_laplacian(n, r):
    # Your code here
    pass

5 test cases · run your code against them in the editor