MediumCalculusca-118

Inverse Laplace Partial-Fraction Coefficients

Problem

Decompose F(s) = (s + c) / ((s - a) * (s - b)) into partial fractions A / (s - a) + B / (s - b).

Cover-up gives A = (a + c) / (a - b) and B = (b + c) / (b - a). Return [A, B]. Assume a != b.

Hint

Evaluate the numerator at each pole after cancelling the corresponding factor.

case 1

in: [1,-2,3]

expected: [1.3333333333333333,-0.3333333333333333]

case 2

in: [0,-1,0]

expected: [0,1]

case 3

in: [2,3,5]

expected: [-7,8]

case 4

in: [-1,1,-1]

expected: [1,0]

Starter codePython

def partial_fraction_coeffs(a, b, c):
    # Return [A, B]
    # Your code here
    pass

4 test cases · run your code against them in the editor