Perfect Square Check

Problem

Return True if n is a perfect square, meaning it equals some integer multiplied by itself, and False otherwise.

Reuse the integer square root and check whether squaring it recovers n exactly. Negative numbers are never perfect squares.

Hint

Floating point square roots can round incorrectly for large inputs, so use integer arithmetic.

case 1

in: [16]

expected: true

case 2

in: [14]

expected: false

case 3

in: [0]

expected: true

case 4

in: [1]

expected: true

case 5

in: [100000000]

expected: true

Starter codePython

def is_perfect_square(n):
    # Your code here
    pass

5 test cases · run your code against them in the editor